find the number of oxygen atoms in 126gm of HNo3
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molecular formula of nitric acid is HNO3
mol. wt.=1(1)+1(14)+3(16)=63gms
63 gm contain 3 oxygen atoms
let 120 gms contain x atoms
then x=(120*3)/63=40/7=5.7(exact)=6 atoms
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umang314:
what's the answer is right
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molecular mass of hno3 is=63 amu
so no of molecule in 126 amu=126/63=2
no of oxygen atoms=2×3=6
no of moles of oxygen atoms=6/6.023×10^23=9.96×10^-24 moles
hope it will help you!!!
so no of molecule in 126 amu=126/63=2
no of oxygen atoms=2×3=6
no of moles of oxygen atoms=6/6.023×10^23=9.96×10^-24 moles
hope it will help you!!!
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