Question

Find the number of oxygen atoms present in 100g of Al2O3 having 80% purity

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Answer 1

Explanation:

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100g of Al2O3 from which 80% in pure..

Weight of Al2O3 = 80g

Moles of Al2O3 = 80/102

It contains 3 oxygen atoms..

3× 80/102

And number of oxygen atoms will be =>

3× 80/102 × Na

2.35 Na

(where Na is Avogadro's number)