find the number of permulations of letter in the following word S H A N T A R A M
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Answer:
In the word 'SHANTARAM', the number of letters is n = 9 of which A repeats thrice, i.e., p = 3 and rest are distinct. Therefore permulations =3.
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0
Answer:
60480
Step-by-step explanation:
in the word 'SHANTARAM', the number of letters is n=9 of which A repeats thrice i.e, p=3 and the rest are distinct.
the number of distinct permutations of the letter
= n!/p!
=9!/3!
=9*8*7*6*5*4*3!/3!
=9*8*7*6*5*4
=60480
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