Math, asked by PorushKKumar, 8 months ago

Find the number of permutations of the letters of the word COMPETITION so that vowels always occurctogether

Answers

Answered by Anonymous
4

Step-by-step explanation:

ANSWER

Rearrange the word PICTURE as PCTRIUE

i)

To keep the vowels together consider IUE as a single unit and the no. of permutation in IUE is 3!

total units become P,C,T,R,IUE = 5

so permutations will be 5!

so total permutations will be 5!*3!

ii)

No two vowels should be together so GIVE GAPS around them like I_U_E

Permutate IUE in 3! ways.

we need two fill in that we will choose from remaining in 4C2 ways

and will consider the selected two and IUE as a single unit and arrange with the remaining 2, so arranging three units is 3!ways

so total ways are - 5C2*3!*3! = 5!*3 = 360ways.

iii)

The relative position is not altered so we need to arrange 3 vowels in 3! ways and 4 consonants in 4! ways give total to be

4!*3!

Answered by Anonymous
24

Answer:

In the word mixture, consider the vowels i,u,e as one letter.

We have mxtr(iue).

The word has 5 letter.And 5 letters can be arranged in 5! ways.  

Now three vowels can be arranged in 3! ways.

The required number of ways are = 5! * 3!

                                                         = 120 * 6

                                                         = 720.

{{You can take help of this question frm above answer.!!!}}

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