Question

find the number of points on x-axis which are at a distance of 2 units from (2,4)

Answer 1

Answer: The answer is 1

Step-by-step explanation:

There is only one point which is at a distance of 2 units from (2,4) on x axis . That is the perpendicular to x-axis !

Answer 2

Answer:

-12

Step-by-step explanation:

Given:

Distance = 2 units

To find:

The number of points

Solution:

Let's talk about how to apply the distance formula when we already know the coordinates to get the distance between two points. The points might only be present in one of the axes—X, Y, or both—or neither. Let's assume that an XY plane contains two points, let's call them A and B. Point A's coordinates are (x1,y1) and Point B's coordinates are ( x2,y2). The following formula is used to determine the distance or space between two places PQ:

Let given points be A$(x_1,y_1)$ and B$(x_2,y_2)$

Thus the distance between the points,

= $\sqrt{(x_2-x_1)^{2}+ (y_2-y_1)^{2}$

Let's look at the x-axis position as (h, 0)

then, given the circumstance

Distance from (h, 0) to (2, 4) is 2 unit.

$=\sqrt{(h-2)^{2}+ (0-4)^{2} } =2\\=\sqrt{(h-2)^{2}+ (4)^{2} } =2\\=(h-2)^{2}+16=4\\ =(h-2)^{2}=-12$

Given that no real number's square can be negative

Therefore, the given equation cannot yield a genuine value for h.

Therefore, there are no points on the x axis that are more than two units away from any other point (2,4).

There are 0 places on the x axis that are 2 units away from (2,4)  Zero .

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