Find the number of positive integers n for which m + 96 is a perfect square. please explain it for a dummy like me of class 6 (I know factorizing)
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Suppose that n2 + 96 = m2 for some positive integer m, then
m2 - n2 = 96
(m - n)(m + n) = 96 = 25 × 3
96 has 12 divisors which come in pairs and since m - n < m + n they are
m - n m + n
1 96
2 48
3 32
4 24
6 16
8 12
For each of the 6 cases solve for m and n and verify which pairs, if any, satisfy your requirements.
Step-by-step explanation:
Hope it helps you......
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