Question

Find the number of positive integers not satisfying the inequality log_2(4^x- 2*2^x 17) > 5

Answer 1

Answer:

Step-by-step explanation:

log2(4^x−2(2^x)+17)>5

4^x−2^x+1+17>32

(2)^2x−2⋅2^x−15>0

(2^x+3)(2^x−5)>0

2^x∈(−∞;−3)∪(5;+∞)⇒x∈(log2^5;+∞)