Question

find the number of real roots of equation (x^2+3)^2-x^2=0
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Answer 1

Step-by-step explanation:

hlo mate here's your answer

Correct option is

A4

Given equation:

x 2

3∣x∣+ 2= 0

When x> 0, we have

x 2

3x+ 2= 0

⇒ (x− 2)(x− 1)= 0

⇒ x= 2 or

x=

1

and when

x<

0,

x 2

3x+ 2= 0

or,

(x+

2)(x+

1)=

0

or,

x=

−2

or

x=

−1

Therefore, number of real roots is 4.

Hence, A is the correct option.

i hope its help you mark as brainlist plz

Answer 2

Answer:

4

Step-by-step explanation:

|x|1 - 3|x| + 2 = 0

let |x| be t , t > 0

to - 3t + 2 = 0

(t-2) × (t-1) = 0

Therefore , t = 2 or 1

where t = 1

|x| = 1

Therefore , x = +1 , -1

When t = 2

|x| = 2

Therefore , x= +2 , -2

So , 4 real roots...