Question

Find the number of real roots of equation (x²+3)² -x²=0​

Answer 1

Answer:

4

∣x∣

2

−3∣x∣+2=0

let∣x∣bet,t≥0

t

2

−3t+2=0

(t−2)(t−1)=0

∴t=2 or 1

wheret=1

∣x∣=1

∴x=+1,−1

whent=2

∣x∣=2

∴x=+2,−2

so4realroots

Step-by-step explanation:

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Answer 2

Answer:

answer may be 4 I think so