Question

Find the number of real roots of equation (x2 + 3)2 – x2 = 0.​

Answer 1

Answer:

Correct option is

A

4

Given equation:

x

2

−3∣x∣+2=0

When x>0, we have

x

2

−3x+2=0

⇒(x−2)(x−1)=0

⇒x=2 or x=1

and when x<0,

x

2

+3x+2=0

or, (x+2)(x+1)=0

or, x=−2 or x=−1

Therefore, number of real roots is 4.

Hence, A is the correct option.