Find the number of real values of x satisfying the equation 2 sin x = x+1/x
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Step-by-step explanation:
2sin x=x+1/x -2<=2 sinx <=2 x+1/x>=2 ; x>0 because of AM>=GM x+1/x<=-2 ; x<0 because of AM>=GM x+1/x=2 when x=1 but at x=1 LHS : 2 sin 1 RHS : 2 similarily, x+1/x=-2 when x=-1 but x=-1 LHS : -2 sin 1 RHS : -2 Hence, No solution.
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