Math, asked by sakshi7777, 1 year ago

find the number of rectangular tiles of size 16cm×12cm required to cover a floor area of size 8m×6m?​

Answers

Answered by Elprimo
21

Answer:


Step-by-step explanation:

Area of rectangular tile =16×12

= 192cm²

Area of floor =8m×6m

=800cm×600cm

=480000cm²

No.of tiles = 480000 ÷ 192

=2500 tiles


Hope it helps

Answered by answerqueen
8
\bold{given : } \\ \\ dimensions \: of \: tile : \\ \\ \bold{length :} \\ \\ 16 \: cm \: \\ \\ \bold{ breadth : }\\ \\ 12 \: cm \: \\ \\ \\ \\
dimensions \: of \: that \: room : \\ \\ \bold{length :} \\ \\ 8 \: m \: \\ \\ 8 \times 100 \: cm \: \\ \\ \bold{800 \: cm} \\ \\ \\ \\ \bold{breadth : }\\ \\ 6 \: m \: \\ \\ 6 \times 100 \: cm \\ \\ \bold{600 \: cm }\: \\ \\ \\ \\
\bold{area \: of \: a \: rectangle :} \\ \\\bold {length \: \times \: breadth \:} \\ \\ \\ \\ \bold{area \: of \: a \: tile : }\\ \\ 16 \times 12 \: {cm}^{2} \\ \\ \\ \\ \bold{area \: of \: the \: room :} \\ \\ 800 \times 600 \: {cm}^{2} \\ \\ \\ \\
\bold{the \: no. \: of \: tiles \: the \: room \: \: can \: hold :} \\ \\\bold{ \frac{area \: of \: the \: room}{area \: of \: a \: tile }} \\ \\ \frac{800 \times 600 \: {cm}^{2} }{12 \: \times 16 \: {cm}^{2} } \\ \\ 50 \times 50 \\ \\ \bold{2500} \\ \\ \\ \\ thus\\ \\ \bold {\: the \: room \: can \: hold \: 2500 \: tiles}
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