Question

find the number of revolution made by a circular wheel of area 6.16 m rolling a distance of 572m

Answer 1

Hi ,

Let radius of the circle = r m

Area of the circle ( A ) = πr² ---( 1 )

Area = 6.16 m²---( 2 )

( 1 ) = ( 2 )

πr² = 6.16 m²

( 22 / 7 ) r² = 616 / 100

r² = ( 616 × 7 )/(100 × 22 )

r² = ( 14 / 10 )²

r = 14 /10

r = 7 / 2 m

Let the number of revolutions = n

One revolution = perimeter of the

circle ( P )

n = 572 / P

n = 572 / ( 2πr )

n = ( 572 × 7 × 5 )/( 2 × 22 × 7)

n = 65

Number of revolutions ( n ) = 65

I hope this helps you.

:)

Answer 2

Answer:

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