Question

find the number of revolution taken by the wheel of an engine of radius 2.8 m that covered the distance of1760m

Answer 1

r= 2.8 m

circumference of circle = 2 pie r
. . . . . . . . . . . . . . . . . . . . . . = 2×22/7×2.8
. . . . . . . . . . . . . . = 17.6 m




no. of revolution = 1760/17.6



=100 revolution

Answer 2

The number of revolution taken by the wheel is 100.

Step-by-step explanation:

Circumference of circle is

$C=2\pi r$

where, r is the radius of the circle.

It is given that the radius of the wheel is 2.8 m.

Substitute r=2.8 and $\pi=\frac{22}{7}$ in the above formula.

$C=2(\frac{22}{7})(2.8)$

$C=17.6$

Let the number of revolution be x.

Distance covered by the wheel in one revolution is 17.6 m. Total distance covered by the wheel in x revolution is 17.6x m.

We need to find the number of revolution taken by the wheel to cover the distance of 1760 m.

$17.6x=1760$

Divide both sides by 17.6.

$x=\frac{1760}{17.6}$

$x=100$

Therefore, the number of revolution taken by the wheel is 100.

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