Question

Find the number of side of a regular polygon whose measure of one angle is 108 degrees and other angles are also same then find their sides

Answer 1

Step-by-step explanation:

Let number of side to be n.

Sum of all angle of polygon = (n-2)180

So, we have,

1 angle of polygon = $\frac{(n-2)180°}{n}$

$\frac{(n-2)180°}{n} = 108°$

$(n-2)180° = 108n$

$180n-360 = 108n$

$180n-108n = 360$

$72n =360$

$n =\frac{360}{72}$

$\boxed{\blue{n = 5}}$