Question

find the number of sides a polygon has if the sum of the measures of the interior angles is (i)50 right angles (ii)1800°.

Answer 1

Answer:

Step-by-step explanation:

(i) 50 right angles= 50x90= 450

Fx for the interior angle sum property= (n-2)180

:. (n-2)180=450

=>n-2=450/180

=> n-2= 2.5

=> n= 4.5 sides( Bruh, what kinda question is this??)

(ii)(n-2)180= 1800

=> n-2= 1800/180

=> n-2= 10

=>n= 12 sides

:)

Answer 2

Step-by-step explanation:

i) 50 right angles

50 right angles =50 ×90

= 4500

The sum of the interior angles of the polygon = (n-2)×180

(n-2)×180=4500

180n-360=4500

180n = 4500 + 360

180n = 4860

n = 4860 / 180

therefore n = 27 answer

ii) 1800

The sum of the interior angles of the polygon = (n-2)×180

=> (n-2) × 180= 1800

=> 180n - 360 = 1800

=> 180n = 1800+ 360

=> 180n = 2160

=> n = 2160/180

therefore n = 12 answer