Find The Number Of Sides Of A Polygon Whose Sum Of Interior Angle Is
1- 28 Right Angle
2- 38 Right Angles
3- 1440°
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Answer:
Given- sum of interior angles = 16 right angles= 16*90=1440
As we know
Sum of interior angles of any polygon = (2n - 4)*90
=> (2n - 4)*90= 16*90 (given)
=> 2n-4 =16
=> 2n= 20
Hence, n= 10
Total number of sides in a polygon =10
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