Find the number of sides of a regular polygon each of its interior angle is 90degrre
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Q. Find the number of sides of a polygon if each interior angle of the polygon is 90°.
Let n be the number of sides of a polygon.
Each interior angle of a regular polygon= n-2×180/n
=> (n-2)×180/n=90° i.e. (n-2)×180=90×n
=> 180n-360=90n
=> 180n-90n=360
=> 90n=360
=> n=360÷90
=> n= 4
Hence the polygon has 4 sides.
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Q. Find the number of sides of a polygon if each interior angle of the polygon is 90°.
Let n be the number of sides of a polygon.
Each interior angle of a regular polygon= n-2×180/n
=> (n-2)×180/n=90° i.e. (n-2)×180=90×n
=> 180n-360=90n
=> 180n-90n=360
=> 90n=360
=> n=360÷90
=> n= 4
Hence the polygon has 4 sides.
Hope it helps!!!...
Please mark my answer as brainliest!!!..
And don't forget to follow me!!!...
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