find the number of sides of a regular polygon if each of us interior and exterior angle is 3:1
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Step-by-step explanation:
let n be the number of sides of the given polygon.
A.T.Q,
(n-2)×180/n÷360/n = 3/1
180n - 360/360 =3/1
180n - 360 = 1080
180n = 1440
n = 1440/180 = 8 sides.
therefore the the given polygon is an octagon.
WHAT STUDENTS SHOULD KNOW TO SOLVE::::::::_______
THE FORMULA FOR THE SUM OF THE INTERIOR ANGLES OF A POLYGON WITH N NUMBER OF SIDES
--------(N-2)×180......TO GET ONE ANGLE WE NEED TO DIVIDE THIS FORMULA BY N...THAT IS WHAT I USED IN THE ABOVE QUESTION.....
AS FOR THE SUM OF EXTERIOR ANGLES,,,,,,,IT IS ALWAYS 360 DEGREE_______THEN TO FIND ONE ANGLE DIVIDE 360 BY N.
HOPE IT HELPS YOU BRO/SIS......
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hope this helps you out
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