find the number of sides of a regular polygon whose each exterior angle is 45 degrees ( I need the workings also)
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Given :
- exterior angle = 45°
We know that ,
The sum of outer angles of any polygon is 360°.
Then,
we have to divide 45 with 360
➝ No. of sides =
➝ 360/45
➝ 8
➝ No.of sides = 8
So, the side is 8
Notes ::
- The sum of the angles of an n sided polygon is ( n - 2 ) × 180°
- The sum of the outer angles of any polygon is 360°
- To find each angle of polygon is Total angle/ sides
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