Find the number of sides of a regular polygon whose each exterior angle has a measure of 45° 5. How many numbers lie between squares of 25 and 26.
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Answer:
sum of exterior angles of any regular polygon=180°
each side of a regular polygon has a exterior angle
thus number of sides =180/45=4
thus it has 4 sides.
square of 26=676
square of 25=625
thus there are 676-625=51 numbers between squares of 25 and 26
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