Question

Find the number of sides of the polygon if sum of its interior angles is:
(i) 10 rt. angles (ii) 20 rt. angles
(iii) 18 rt. angles (iv) 28 rt. angles​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

i)10 rt angles

= 10*90°= 900°

(n-2)*180°=900°

n-2= 900°/180°

n-2= 5

n= 5+2=7

number of sides 7

ii)20 rt angles

= 20*90°=1800°

(n-2)*180°=1800°

n-2= 1800°/180°

n-2= 10

n= 10+2=12

numbers of sides 12

iii) 18 rt angles

= 18*90°= 1620°

(n-2)*180°=1620°

n-2= 1620°/180°

n-2= 9

n= 9+2=11

numbers of sides 11

iv)28 rt angles

= 28*90°= 2520°

(n-2)*180°=2520°

n-2= 2520°/180°

n-2=14

n= 14+2= 16

numbers of sides 16