find the number of sides of the regular polygon whose each interior angle is 140 degree
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Interior angle =140
Sum of all interior angles = 140*4
= 560
(2n-4)90 = 560
2n-4= 560/90
2n-4 = 6
2n=6+4=10
n=10/2
n= 5
Sum of all interior angles = 140*4
= 560
(2n-4)90 = 560
2n-4= 560/90
2n-4 = 6
2n=6+4=10
n=10/2
n= 5
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