Find the number of small cubes with edge 20 cm that can be accommodated in a cubical box of 2 metre edge
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Answered by
5
Heya !!!
Here is your answer,
Edge of small cube = 20 cm
Volume of small cube = (side)³
= (20)³ =2×2×2 = 8000 cm³
Edge of big cube = 2 m = 200 cm
( 1 m = 100 cm
So, 2 m = 2×100 = 200cm )
Volume of big cube = (side)³
= (200)³ = 200×200×200 = 8000000 cm³
Number of small cube accommodate in big cube
= 8000000/8000 = 1000
Hence, 1000 cubes will be accommodate in a cubical box of 2m edge.
Hope it helps.
Here is your answer,
Edge of small cube = 20 cm
Volume of small cube = (side)³
= (20)³ =2×2×2 = 8000 cm³
Edge of big cube = 2 m = 200 cm
( 1 m = 100 cm
So, 2 m = 2×100 = 200cm )
Volume of big cube = (side)³
= (200)³ = 200×200×200 = 8000000 cm³
Number of small cube accommodate in big cube
= 8000000/8000 = 1000
Hence, 1000 cubes will be accommodate in a cubical box of 2m edge.
Hope it helps.
Answered by
3
volume of cubical box= 2×2×2 m cube
8 m cube= 8000000 cm cube
volume of each small cube=8000 cm cube
therefore no of small cubes that can b accommodated= 8000000÷8000
=1000
8 m cube= 8000000 cm cube
volume of each small cube=8000 cm cube
therefore no of small cubes that can b accommodated= 8000000÷8000
=1000
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