Chemistry, asked by shehabeldin2006, 10 hours ago

Find the number of sodium ions produced from dissolving 117gm of sodium chloride

Answers

Answered by prakhar941230

Answer:The number of sodium and chloride ion present in 117 gram of sodium chloride is equal to 12.046x10²³

Explanation:

The molecular formula of sodium chloride is NaCl. as a result of this the molecular weight of sodium chloride is 23 + 35.5 = 58.5.

Therefore in 117 gram of sodium chloride there is 2 x avogadro number of each of the following iron which constitutes sodium chloride. = 2x6.023 x10²³ = 12.046x10²³

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Answered by farruminoo

Answer:

The number of sodium and chloride ion present in 117 gram of sodium chloride is equal to 12.046x10²³

Explanation:

The molecular formula of sodium chloride is NaCl. as a result of this the molecular weight of sodium chloride is 23 + 35.5 = 58.5.

Therefore in 117 gram of sodium chloride there is 2 x avogadro number of each of the following iron which constitutes sodium chloride. = 2x6.023 x10²³ = 12.046x10²³

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