find the number of solution of the following pair of linear X + 2 Y - 8 is equal to zero 2 X + 4 Y is equal to 16
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Answer:
Step-by-step explanation:
Coefficients of the equation x + 2y − 8 = 0 are a1 = 1, b1 = 2 and c1 = -8
2x + 4y = 16 ⇒ 2x + 4y - 16 = 0
Coefficients of the equation 2x + 4y - 16 = 0 are a2 = 2, b2 = 4 and c2 = -16
a1/a2 = 1/2, b1/b2 = 2/4 = 1/2, c1/c2 = -8/-16 = 1/2.
∴ a1/a2 = b1/b2 = c1/c2
Hence, there are infinitely many solutions to the pair of linear equations.
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let's make a equation.
x+2y=8 .....eq 1
2x+4y=16.......eq 2
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