Question

Find the number of solution of x2 + | − 1| =1? ​

Answer 1

x

x 2

x 2 +∣x−1∣=1

x 2 +∣x−1∣=1If x−1≥0⇒x≥1

x 2 +∣x−1∣=1If x−1≥0⇒x≥1x

x 2 +∣x−1∣=1If x−1≥0⇒x≥1x 2

x 2 +∣x−1∣=1If x−1≥0⇒x≥1x 2 +x−1=1

x 2 +∣x−1∣=1If x−1≥0⇒x≥1x 2 +x−1=1x

x 2 +∣x−1∣=1If x−1≥0⇒x≥1x 2 +x−1=1x 2

x 2 +∣x−1∣=1If x−1≥0⇒x≥1x 2 +x−1=1x 2 +x−2=0

x 2 +∣x−1∣=1If x−1≥0⇒x≥1x 2 +x−1=1x 2 +x−2=0(x+2)(x−1)=0x=−2,1x=−2, Not possible,So, x=1 is a solution.If x−1<0⇒x<1x 2 +1−x=1x 2 −x=0x=0,1x=0 is also a solution x=0, 1 solutions.2 solutions.

therefore the answer is =0

Answer 2

Answer:

|-1|=1

so, x^2+1=1

=> x^2=0

=> x=0

Hence one solution.