Question

Find the number of solutions for the pair of linear equations. x+2y-8=0. and. 2x+3y=16
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Answer 1

Step-by-step explanation:

I have given answer...

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Answer 2

Answer:

Step-by-step explanation:

x + 2y - 8 =  0

⇒ So a1 = 1 , b1 = 2 and c1 = -8

2x + 3y = 16

∴ 2x + 3y - 16 = 0

⇒ So,  a2 = 2 , b2 = 3 and c2 = -16

∴  $\frac{a1}{a2} = \frac{1}{2}$

$\frac{b1}{b2} = \frac{2}{3}$

$\frac{c1}{c2} = \frac{-8}{-16} = \frac{1}{2}$

since , $\frac{a1}{a2} \neq \frac{b1}{b2}$

The following linear equation has definite solutions..

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