Question

find the number of solutions for x+1/y-2 and 2xy-3y+2

Answer 1

Answer:

(2)²+ 2(2×-2)-3(-2)²

4+2(-4)-3(4)

4-8-12

= -16

So, the answer will be -16

Step-by-step explanation:

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Answer 2

Answer:

x+1/y =2. 2xy-3y=--2

x=2--1/y

= (2y-1)/y

2(2y-1)/y -3y = --2

4y-2 — 3y^2 =-2y

QUADRATIC EQUATION

-3y^2 +6y -2 =0

3y^2 -6y +2=0

a=3 b=--6 c=2

y=[ 6+ or --sqare root (36 -24)]/6

y= [6+(12)^1/2 ]/6. [ 6--(12)^1/2]/6

y=(6+3.46)/6 = 9.46/6 =1.57.

y=(6--3.46)/6 =2.54/6 =0.42

x+1/y =2

x=2--1/y =2 -1.57=0.43.

Step-by-step explanation:

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