Math, asked by mandalsamir05, 1 month ago

Find the number of solutions of 2^x+3^x+4^x-5^x=0. Correct answer will be marked brainliest. Please don't spam.​

Answers

Answered by puzzler4578
10

Answer:

2 x +3 x +4 x−5 x =0

⇒2 x +3 x +4 x =5 x

⇒(

5

2

)

x

+(

5

3

)

x

+(

5

4

)

x

=1

Answered by andrea76
5

2^x+3^x+4^x-5^x=0 \\  {2}^{x}  +  {3}^{x} +   {4}^{x}  =  {5}^{x}  \\ ( \frac{2}{5} ){}^{x}  + ( \frac{3}{5}  {}^{} )  {}^{x}  + ( \frac{4}{5} ) {}^{x}  = 1

Now \\ the number of solutions of the equation is equal to number of times.

From the graph, equation has only one solution.

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