Question

Find the number of solutions of the equation 2x+y=40 where both x and y are positive integers and x<=y

Answer 1

Answer:

2x-y = 40

Add y to both sides.

2x=40+y

The equation is in standard form.

2x=y+40

Divide both sides by 2.

\frac{2x}{2}=\frac{y+40}{2}

Dividing by 2 undoes the multiplication by 2.

x=\frac{y+40}{2}

x=\frac{y}{2}+20

Answer 2

Step-by-step explanation:

if x=1… then 2×1+y=40

2+y=40

y=40-2

y=38

x=20 then y=0

x=10 then y=20