Find the number of solutions of the equation 2x+y=40 where both x and y are positive integers and x<=y
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Answered by
1
Answer:
2x-y = 40
Add y to both sides.
2x=40+y
The equation is in standard form.
2x=y+40
Divide both sides by 2.
\frac{2x}{2}=\frac{y+40}{2}
Dividing by 2 undoes the multiplication by 2.
x=\frac{y+40}{2}
x=\frac{y}{2}+20
Answered by
1
Step-by-step explanation:
if x=1… then 2×1+y=40
2+y=40
y=40-2
y=38
x=20 then y=0
x=10 then y=20
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