Question

Find the number of solutions of the following pair of linear equations:



2x + 3y = 4 and 4y +6x = 8 .​

Answer 1

Answer:

u can any thing.

Step-by-step explanation:

1 take first equation 2x+3y=4 now take x=o and substitute 2(0)+3y=4 next 0+2y=3 now transpose

y=3/2 (0,3/2) amd next take y=0 and substitute

2x+3(0)=4 next 2x+0=4 now transpose x=4/2 cutting y=2 (2,0)

for secound

4y+6x=8

1 take x=0

4(0)+6x=8

0+6x=8

6x=8

x=8/6 cuttings 4/3 ,,x=4/3

same as u can take x=1 and y=2 etc..

hope it helps