Find the number of sqaure tiles of size 15 cm required for covering the floor of a room 9 m long and 6 m wide.Find also the cost of the tiles required if one tile costs 4.50
Answers
The length of the room =9m
The breadth of the room =6m
As it is a rectangle, the formula for finding the area is l*b(l represents the length and b represents the breath)
So, area=l*b
=9*6
=54
Therefore, the area of the room is 54 sq m
Now we have to find the area of tile
The side of a tile =15cm(As the shape of the tile is a square)
As it is a square , the formula for finding the area is s^2(s represents the side of the square )
So, area=s^2
=15^2
=225
Therefore, the area of a tile is 225 sq cm
We have to convert the area of the room from sq m to sq cm
So, area of the room = 15 *10000 =150000 sq cm (As one sq m is equal to 10000 sq cm)
Number of tiles required for covering the floor =150000 / 225
=666.666667(approx. 667 tiles)
If one tile cost ₹4.50
667 tiles will cost=667 * 4.50=3001.50
Therefore the he cost of tiles required is ₹3001.5
HOPE THIS WILL HELP YOU
Answer:
Area of floor = 36×24=864 sq. m
Area of one tile = 6×6=36 sq. m.
Therefore,
Tiles required =
36
864
=24 tiles