Question

Find the number of square tiles of size 8 cm required to cover a wall 10m by 6m.​

Answer 1

Answer:

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Answer 2

$\bf\green{QuestioN:-}$

Find the number of square tiles of size 8 cm required to cover a wall

10m by 6m.​

$\bf\red{AnsweR:-}$

Given :

Size of square tiles = 8 cm

Length of the wall = 10 m

Breadth of the wall = 6 m

To Find :

No. of square tiles required to cover the wall.

Solution :

• Size of the square tiles = 8 cm.

• So the area of the tile,

• Side × side = 8 × 8 = 64 cm ²

• Length of the wall = 10 m

• Breadth of the wall = 6 m.

The units of measures of the tile and wall is in different units.

So we need to convert these measure into cm.

Then,

• Length of the wall = 10 m

As we know,

$\large{\boxed{\boxed{\bf{1\:m=100\:cm}}}}}$

• ∴ Length = 10 m = 10 × 100 = 1,000 m

Like this,

• Breadth = 6 m

• Breadth = 6 × 100 = 600 cm.

Then,

⇒ The area of the wall = Length × Breadth

⇒ Area of the wall = 1,000 × 600 cm²

⇒ Area of the wall = 6,00,000 cm ²

Now, the final step,

$\large{\boxed{\boxed{\bf{\longrightarrow{No.\:of\:tiles\:required=\dfrac{Area\:of\:wall}{Area\:of\:tile}}}}}$

$\large{\boxed{\boxed{\bf{\longrightarrow{No.\:of\:tiles\:required=\dfrac{6,00,000}{64}}}}}}$

$\huge{\boxed{\boxed{\bf{\longrightarrow{9,375}}}}}$

9, 375 tiles are required to cover the wall.

All Done !!☺