find the number of square tiles size 10 cm required to cover a room 5m long 4m wide. Find the cost for covering the room if each square tile costs rupees 5.00.
Answers
Answer:
2000 tiles
₹10000
Step-by-step explanation:
Length and Breadth of room = 500cm , 400cm
Area of room = L×B
= 500 × 400
= 2,00,000cm²
Area of square tiles = 10×10
= 100cm²
No. of tiles required = 20000/100
= 200 tiles per cm
Cost of tiles = 2000×5
= ₹10000
Explaination:
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Answer:
The correct option is B
75 tiles, $525
Length of the room = 8 m
Breadth of the room = 6 m
Area of the room = 8
×
6 m
2
{Area of room = Area of tiles that are put on the floor of the room.}
= 48 m
2
Area of one square tile = 0.8 m
×
0.8 m= 0.64 m
2
Number of tiles required =
A
r
e
a
o
f
f
l
o
o
r
A
r
e
a
o
f
t
i
l
e
s
=
48
0.64
= 48
×
100
64
= 75 tiles
For 1 tile, the cost of tiling is $7
For 7 tiles, the cost of tiling is $(7
×
75) = $525