Question

Find the number of straight lines perpendicular to the line 2x-3y+6=0..​

Answer 1

Answer:

don't know this answer

Answer 2

Step-by-step explanation:

A line that has perpendicular slope will have a product of -1 when multiplied by the slope of another line.

First, find the slope of the given line in the equation:

2x + 3y = 6

Solve for y:

Subtract 2x from both sides, then divide by 3

3y = 6–2x

y = 3-(2/3)x, or y = -(2/3)x+3

The slope is -2/3, so the product of the perpendicular slope and this slope must equal -1. How to find it? Easy: just flip the equation and get rid of the - sign to get:

3/2

-(2/3)*3/2 = (-2*3)/(3*2) = -6/6 = -1

Bam! So the slope of the perpendicular line is 3/2