Find the number of terms common to the two A.P.'s 3, 7, 11, ...... 407 and 2, 9, 16, ......, 709.
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Answer:
102
Step-by-step explanation:
In first case
let a=3, an=407
common difference(cd)=7-3
=4
an=a+(n-1)d
407=3+(n-1)4
407=3+4n-4
407=4n-1
407+1= 4n
408= 4n
n=408÷4
n=102
In the second case
a=2,an=709
common difference=9-2
=7
an=a+(n-1)d
709=2+(n-1)7
709=2+7n-7
709=7n-5
709+5=7n
714=7n
n=714÷7
n=102
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