Question

find the number of terms each
of the following aps. 7,13,19....205

Answer 1

no. of aps = n
a = 7
an (l) = 205
simply by applying the formula an = a + (n-1) d,
we get
205 = 7 + (n -1) d. ....................1

Now calculate d ,
d= a2 - a1
= 13 -7 = 6

putting in eqn 1 ,
205 = 7 +( n -1 ) 6
205 = 7 + 6n -6
205 -1 = 6n
204 / 6 =n
34 =n
hence. the no. of terms in ap is 34...
hope it helps
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Answer 2

Question:-

Find the number of terms each of the following A.P. 7,13,19....205.

$\huge{ \star\:{\underline{\boxed{\mathfrak{\purple{ Answer}}}}}}$

Given:-

• a = 7 ( first term )
• d = a2 - a1 = 13 - 7 = 6
• an = 205 ( last term )

To find:-

• Number of terms

______________________

$\large \star \: a_n = a + (n - 1)d$

$\large \star \: 205 = 7 + (n - 1)6$

$\large \star \: 198 = (n - 1)6$

$\large \star \: 33 = n - 1$

$\large \star \: n \: = 34$

-------------------_---------------

➦ So there are 34 terms is this A.P