Math, asked by simransingh67125, 20 days ago

find the number of terms in 4,9,14,19...,,127

Answers

Answered by khairnartejas2408

0

Step-by-step explanation:

a(initial term)=4

common difference=5

tn=127

tn=a+(n-1)d

127=4+(n-1)5

123=5n-5

n=128/5

which means the sequence in not in ap

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