Question

Find the number of terms in an AP given that its first and last terms are a and 37a respectively and that its common difference is 4a​

Answer 1

Answer:

AP 46 is your answer..............

Answer 2

Answer:

In an A.P., uₙ = a + (n-1)d

first term = a

common difference = d = 4a

last term = uₙ = 37a

uₙ = 37a

a + (n-1) (4a) = 37a

(n-1)(4a) = 36a

n - 1 = 9

n = 10

Therefore, there are 10 terms in that A.P.