Math, asked by williamkamong17, 3 months ago

Find the number of terms in an arithmetics sequence with a=5, d=2 and the last term 43

Answers

Answered by vedu0731
1

Answer:

n= 5

Step-by-step explanation:

an= a + (n-1) d

43= 5 + (n-1) 2

43-5 = 2n-2

8 = 2n -2

8+2 = 2n

10/ 2 = n

n = 5

Answered by rajenrashmi74
1

a=5,d=2 and an=43 n=?

=>an=a+(n-1)d

=>43=5+(n-1)2

=>43-5=(n-1)2

=>38=(n-1)2

=>38/2=n-1

=>19=n-1

=>19+1=n

=>20=n

therefore no of terms in this ap is 20

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