find the number of terms in AP, 100,96,92,........,12
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Answered by
7
heya it's Aastha.....
◆In an A.P :-
a = 100, d = -4 . an = 12 .
an = a +( n-1 ) d
12 = 100 + (n-1) -4
-88/-4 = n-1
22+1 = n
n = 23 .....
I hope it help you
◆In an A.P :-
a = 100, d = -4 . an = 12 .
an = a +( n-1 ) d
12 = 100 + (n-1) -4
-88/-4 = n-1
22+1 = n
n = 23 .....
I hope it help you
neha339:
tq
Answered by
4
a=100,d=96-100=-4
12=100+(n-1)(-4)
12-100=4-4n
-88-4=-4n
-92=-4n
n=23
12=100+(n-1)(-4)
12-100=4-4n
-88-4=-4n
-92=-4n
n=23
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