find the number of terms in ap 100,96,92....12
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l=12,a=100,d=96-100=-4,n=?
l=[a+(n-1)d]
12=100+(n-1)-4
12=100-4n+4
12=104-4n
-4n=12-104
-4n=-92
n=23.
Therefore,no.of terms = 23
l=[a+(n-1)d]
12=100+(n-1)-4
12=100-4n+4
12=104-4n
-4n=12-104
-4n=-92
n=23.
Therefore,no.of terms = 23
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