Find the number of terms in AP, -2, 3, 8...........288. find their sum
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Answered by
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a = -2
d= 3 - (-2) = 3 + 2 = 5
last term = 288
=>288 = -2 + (n-1)5
=>(n-1)5 = 230
=> n-1 = 46
=> n = 47
no of terms = 47
sum = 47/2 [-2+288]= 47[286/2]
= 47(143)=6721
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Answered by
0
tn=288 ,a=-2,d=5
by formula.
tn =a+(n-1)d
288=-2+(n-1)×5
288+2=(n-1)×5
290÷5=(n-1)
58=(n-1)
n=58+1
n=59.
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