find the number of terms in each of the following APs (1). 7 ,13,19,205
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A.P 7,13,19,...205
a=7
d= 13-7=6
An= 205
As we know,
An=a+(n-1)d
205=7+(n-1)d
=205-7 =(n-1)6
198=(n-1)6
n-1= 198/6
n-1=33
n=33+1
n=34.
thus total no. of terms is 34.
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