Find the number of terms in following :
( 2x 3y )19
( 1 x2 2x )10
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⭐⭐ Here is ur answer ⭐⭐
The number of terms in the expansion of (a + b)n is n + 1.
So, number of terms in the expansion of (2x + 3y)19 = 19 + 1 = 20
(1 + x2 + 2x)20 = [(1 + x)2]20 = (1 + x)40
So, number of terms in expansion of (1 + x2 + 2x)20 = Number of terms in expansion of (1 + x)40 = 40 + 1 = 41
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The number of expansion = (a+B)n is n+1
So,
Number of terms in expansion = (2x+3y)19
=19+1
=20
(1+x2+2x)20
=[(1+x)2]20
=(1+x)40
Number of terms in expansion
(1+x)40
= 40+1
= 41
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