Question

Find the number of terms in following :

( 2x 3y )19( 1 x2 2x )10

Answer 1

$\huge{Hey Mate!!!}$

☆☞ Here is ur answer ☜☆

☆☞ The number of terms in the expansion of (a + b)n is n + 1.

So, number of terms in the expansion of (2x + 3y)19 = 19 + 1 = 20

 

(1 + x2 + 2x)20 = [(1 + x)2]20 = (1 + x)40

 

So, number of terms in expansion of (1 + x2 + 2x)20  = Number of terms in expansion of (1 + x)40 = 40 + 1 = 41

 

CHEERS!!!

Answer 2

heya!!

here is your answer ⤵️⤵️

given,

(2x 3y)19 ( 1x2 2x)10.

The no.of expansions = (a+b)is (n+1).

No of terms in expansion

= ( 2x+3y)19.

= 19+ 1

= 20

( 1+x2+ 2x) 20

=(1+x)2) 20

= (1+x)40.

= 40+1

= 41


hope my answer helps you ✌