Question

find the number of terms in the AP 1 3 5. 1001.​

Answer 1

a=1

d=3-1=2

1001=1+(n-1)2

n-1=500

n=501

Answer 2

Step-by-step explanation:

Given Find the number of terms in the AP 1 3 5. 1001.

In an arithmetic sequence the sum of n terms is given by Tn = a + (n – 1)d

Now here a = 1 and d = 2  

Also number of terms is 1001

So 1001 = (1) + (n – 1) 2

1001 = 1 + 2 n - 2

1001 = 2 n – 1

So 2 n = 1002

Or n = 1002 / 2

Or n = 501

the number of terms in the AP are 501

Reference link will be

https://brainly.in/question/14333770