find the number of terms in the following G.P.
1.) 4,8,16,...,8192.
2.) 1/3,1/9,1/27,...,1/2187.
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añ=a¹(r)^(n-1)
1. a¹=4; añ=8192; r=8/4=2
8192=4(2)^(n-1)
2^(n-1)=8192/2
2^(n-1)=4096
2^(n-1)=2^12
since base is same, equate the exponents
n-1=12
n=13
2. a¹=1/3; añ=1/2187; r=1/9÷1/3 =1/3
1/2187=1/3×(1/3)^n-1
1/729=(1/3)^n-1
(1/3)^6=(1/3)^n-1
n-1=6
n=7
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