Question

find the number of terms in the given G.P

$\frac{1}{3} . \: \frac{1}{9}. \: \frac{1}{27}........is \: \frac{1}{19683}$
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Answer 1

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Answer 2

Answer:

★ Here a = 1/3 and r = 1/9 - 1/3 = 1/3

Let the nth term of this sequence is 1/19683

By Using Formula

➟ an = a r(n-1 )

➟ 1/19683 = 1/3 * (1/3)(n-1)

➟ 1/6561 = (1/3)(n-1)

➟ (1/3)8 = (1/3)n-1

➟ 8 = n -1

➟ n = 9

So , that Will be 9th Term .